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## Homework Statement

use a double integral to find the volume of the solid bounded by.

z=x^2+2y^2 and z=12-2x^2-y^2

I want to change variables using polar coordinates, I know its the top minus the bottom, and the intersection between the two is a circle radius 2.

## The Attempt at a Solution

I want to make sure i have the correct set up

[itex]\int^{2\pi}_{0}[/itex] [itex]\int^{2}_{0}[/itex] (12-3r[itex]^{2}[/itex])rdrd[itex]\theta[/itex]